For each proposed reaction, (E^circ_{cell}=E^circ_{cathode}-E^circ_{anode}). A positive value indicates a feasible spontaneous reaction under standard conditions.
(a) (E^circ=0.77-0.54=+0.23,mathrm{V}). Hence (mathrm{Fe^{3+}}) oxidises (mathrm{I^-}); the reaction is feasible.
(b) (E^circ=0.80-0.34=+0.46,mathrm{V}). Hence (mathrm{Ag^+}) oxidises Cu; the reaction is feasible.
(c) (E^circ=0.77-0.34=+0.43,mathrm{V}). Hence (mathrm{Fe^{3+}}) oxidises Cu; the reaction is feasible.
(d) For Ag to be oxidised while (mathrm{Fe^{3+}}) is reduced, (E^circ=0.77-0.80=-0.03,mathrm{V}). The reaction is not feasible as written.
(e) (E^circ=1.09-0.77=+0.32,mathrm{V}). Hence (mathrm{Br_2}) oxidises (mathrm{Fe^{2+}}); the reaction is feasible.
Final answers by part(a) Fe^{3+}/I^-: feasible(b) Ag^+/Cu: feasible(c) Fe^{3+}/Cu: feasible(d) Ag/Fe^{3+}: not feasible as written(e) Br_2/Fe^{2+}: feasible.