Translate every condition into an equation and retain exact values throughout the ellipse calculation.
\[\frac{x^2}{4}+\frac{y^2}{25}=1\]
\[\begin{aligned}a &= 5,b\\&= 2,c\\&= \sqrt{21}\end{aligned}\]
\[\begin{aligned}c^2 &= a^2-b^2,\quad e\\&= \frac ca,\quad\ell\\&= \frac{2b^2}{a}\end{aligned}\]
\[\begin{aligned}F &= (0,\pm\sqrt{21}),\ V\\&= (0,\pm5),\ 2a\\&= 10,\ 2b\\&= 4,\ e\\&= \frac{\sqrt{21}}5,\ \ell\\&= \frac85\end{aligned}\]
The last line satisfies the original conditions and supplies every requested part.
Final answer\[F=(0,\pm\sqrt{21}),\ V=(0,\pm5),\ 2a=10,\ 2b=4,\ e=\frac{\sqrt{21}}5,\ \ell=\frac85\]