Translate every condition into an equation and retain exact values throughout the ellipse calculation.
\[\begin{aligned}4x^2+9y^2 &= 36\Rightarrow\frac{x^2}{9}+\frac{y^2}{4}\\&= 1\end{aligned}\]
\[\begin{aligned}a &= 3,b\\&= 2,c\\&= \sqrt5\end{aligned}\]
\[\begin{aligned}c^2 &= a^2-b^2,\quad e\\&= \frac ca,\quad\ell\\&= \frac{2b^2}{a}\end{aligned}\]
\[\begin{aligned}F &= (\pm\sqrt5,0),\ V\\&= (\pm3,0),\ 2a\\&= 6,\ 2b\\&= 4,\ e\\&= \frac{\sqrt5}{3},\ \ell\\&= \frac83\end{aligned}\]
The last line satisfies the original conditions and supplies every requested part.
Final answer\[F=(\pm\sqrt5,0),\ V=(\pm3,0),\ 2a=6,\ 2b=4,\ e=\frac{\sqrt5}{3},\ \ell=\frac83\]