In the diagram, \(P\) lies on \(QT\) and \(S\) lies on \(QR\). It is given that
Prove that \(\triangle PQS\sim\triangle TQR\).
Solution to Question 1831
Complete workingIn \(\triangle PQR\), \(\angle PQR=\angle PRQ\). Sides opposite equal angles are equal; therefore,
Using \(1\) in the given proportion,
Because \(P\) lies on \(QT\) and \(S\) lies on \(QR\),
Equations \(2\) and \(3\) give two proportional sides including an equal angle. Hence \(\triangle PQS\sim\triangle TQR\) by SAS similarity.
Therefore, \(\triangle PQS\sim\triangle TQR\) by SAS similarity.
