Glass has refractive index 1.50. Calculate light speed in it when \(c=3.00\times10^8\text{ m s}^{-1}\).
Solution to Question 401
Complete working\(n=\frac{c}{v}\), therefore
\(2.00\times10^8\text{ m s}^{-1}\).
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Glass has refractive index 1.50. Calculate light speed in it when \(c=3.00\times10^8\text{ m s}^{-1}\).
\(n=\frac{c}{v}\), therefore
\(2.00\times10^8\text{ m s}^{-1}\).
Children with light eyes are often found to have light-eyed parents. Does this observation establish whether light eye colour is dominant or recessive?
No. A resemblance correlation alone gives no controlled crosses, parental genotypes or offspring ratios. Both a dominant allele shared by parents and a recessive allele inherited from carrier/affected parents can produce the observation. A larger pedigree with known relationships and segregation patterns is required.
Differentiate pollination from fertilisation.
Pollination is transfer of pollen grains from anther to stigma and may occur by wind, water or animals. Fertilisation occurs later, after pollen germination: a male gamete travels through the pollen tube and fuses with the egg in an ovule to form a zygote. Pollination is transfer; fertilisation is gamete fusion.
Name one plant hormone that promotes growth.
Auxin promotes cell elongation, particularly in shoots. Gibberellins and cytokinins are also growth-promoting hormones.
Auxin.
What is the function of digestive enzymes?
Most food molecules are too large and insoluble to cross the intestinal wall. Digestive enzymes catalyse hydrolysis: carbohydrates to simple sugars, proteins to amino acids and fats to fatty acids plus glycerol. These small soluble products can be absorbed and assimilated.
They break large insoluble food molecules into small soluble, absorbable molecules.
Why is conversion of ethanol into ethanoic acid classified as oxidation?
During the change, ethanol gains oxygen and loses hydrogen:
Gain of oxygen or loss of hydrogen is oxidation. Acidified potassium dichromate or alkaline potassium permanganate supplies the oxygen.
Ethanol is oxidised because it gains oxygen and loses hydrogen to form ethanoic acid.
(i) Show the valence electrons of sodium, oxygen and magnesium using electron-dot notation. (ii) Use electron transfer to explain formation of sodium oxide and magnesium oxide. (iii) Name the ions in each compound.
Na has one valence electron, O has six, and Mg has two. Two sodium atoms each transfer one electron to an oxygen atom:
Thus \(\ce{Na2O}\) contains \(2\ce{Na+}\) and \(\ce{O^{2-}}\).
One magnesium atom transfers both valence electrons to oxygen:
Thus \(\ce{MgO}\) contains \(\ce{Mg^{2+}}\) and \(\ce{O^{2-}}\). In each case the ions acquire stable noble-gas configurations.
\(\ce{Na2O}: 2Na+\) and \(\ce{O^{2-}}\); \(\ce{MgO}: Mg^{2+}\) and \(\ce{O^{2-}}\).
When preparing a dilute acid, why must concentrated acid be added slowly to water rather than adding water to the acid?
Dilution of a concentrated acid releases a large amount of heat. When acid is added slowly to a larger volume of water with continuous stirring, the water absorbs and disperses the heat safely.
If a small quantity of water is poured into concentrated acid, that water can heat suddenly, boil and splash corrosive acid out of the container. Therefore acid is always added to water, preferably along the side of the vessel.
Add acid slowly to water because dilution is highly exothermic and this order prevents violent boiling and splashing.
For y=3.0sin(36t+0.018x+π/4), with x,y in cm, write y(t) at x=0,2,\(4\,\mathrm{cm}\). Compare the three time graphs.
Principle. Insert each fixed x. Every point retains \(A=3.0\,\mathrm{cm}\) and ω=36 rad s⁻¹; position changes only phase.
All are sinusoidal with frequency 36/(2π)=5.73 Hz and amplitude \(3.0\,\mathrm{cm}\). Their phase increases by kΔx, so different points reach corresponding states at different times.
A \(1.8\,\mathrm{m}\) brass wire of diameter \(2.0\,\mathrm{mm}\) is fixed between rigid supports at 27°C with negligible initial tension, then cooled to −39°C. Find the tension; α=2.0×10⁻⁵ K⁻¹ and Y=0.91×10¹¹ Pa.
Principle. The supports prevent the free thermal contraction α|ΔT|. The same magnitude becomes tensile mechanical strain, giving stress Yα|ΔT|.
Tension ≈ 3.8 × 10² N.