Given P(A)=0.42, P(B)=0.48 and P(A∩B)=0.16, find P(A′), P(B′), and P(A∪B).
Solution to Question 1071
Complete workingDefine the sample space and count each favourable outcome once.
The final value lies in [0,1]; complement pairs also sum to one, providing an independent check.
