Use N = nNₐ. A helium atom has a mass of about 4 u, while 1 mol He has a mass of about \(4\,\mathrm{g}\).
\[\begin{aligned}(i) \quad N &= 52(6.022\times10^{23})\\&= 3.131\times10^{25}\end{aligned}\]
\[\begin{aligned}(ii) \quad N &= \frac{52\ \mathrm u}{4\ \mathrm{u\,atom^{-1}}}\\&= 13\ \mathrm{atoms}\end{aligned}\]
\[\begin{aligned}(iii) \quad n &= \frac{52}{4}\\&= 13\ \mathrm{mol}\end{aligned}\]
\[\begin{aligned}N &= 13(6.022\times10^{23})\\&= 7.829\times10^{24}\end{aligned}\]
Final answers by part\[(i) \ 3.13\times10^{25};\quad(ii) \ 13;\quad(iii) \ 7.83\times10^{24}\ \mathrm{atoms}\]