Translate every condition into an equation and retain exact values throughout the ellipse calculation.
\[\begin{aligned}36x^2+4y^2 &= 144\Rightarrow\frac{x^2}{4}+\frac{y^2}{36}\\&= 1\end{aligned}\]
\[\begin{aligned}a &= 6,b\\&= 2,c\\&= 4\sqrt2\end{aligned}\]
\[\begin{aligned}c^2 &= a^2-b^2,\quad e\\&= \frac ca,\quad\ell\\&= \frac{2b^2}{a}\end{aligned}\]
\[\begin{aligned}F &= (0,\pm4\sqrt2),\ V\\&= (0,\pm6),\ 2a\\&= 12,\ 2b\\&= 4,\ e\\&= \frac{2\sqrt2}{3},\ \ell\\&= \frac43\end{aligned}\]
The last line satisfies the original conditions and supplies every requested part.
Final answer\[F=(0,\pm4\sqrt2),\ V=(0,\pm6),\ 2a=12,\ 2b=4,\ e=\frac{2\sqrt2}{3},\ \ell=\frac43\]